What is the limit as x approaches 4 of sqrt(x^2+9) ?

The limit as x approaches 4 of sqrt(x^2+9) is 5

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limit as x approaches 4 of sqrt(x^2+9)

x \to 4 lim (x^{2} + 9)

5

Solution steps

x \to 4 lim (x^{2} + 9)

Plug in the value

x = 4

= 4^{2} + 9

Simplify

4^{2} + 9 : 5

= 5

f (x) = (5 + x^{4})^{3 x}

\frac{\partial}{\partial y} (x^{3} + k y^{2} - 5 x y)

\frac{d}{d x} ((x^{2} - 7)^{2})

y = - \frac{8 x}{x ^{2} + 1}

f (x) = \frac{e ^{x}}{x + 6}, (0, \frac{1}{6})

What is the limit as x approaches 4 of sqrt(x^2+9) ?
The limit as x approaches 4 of sqrt(x^2+9) is 5