What is the derivative of x^3-6x ?

The derivative of x^3-6x is 3x^2-6

What is the first derivative of x^3-6x ?

The first derivative of x^3-6x is 3x^2-6

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\frac{d}{d x} (x^{3} - 6 x)

3 x^{2} - 6

Solution steps

\frac{d}{d x} (x^{3} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x) = 6

= 3 x^{2} - 6

x \to 0 - lim (12 e^{\frac{- 2}{x}})

\int e^{- \frac{x}{0.2}} d x

\int \frac{t}{t + 3} d t

\int_{5}^{6} x x - 5 d x

\int \frac{2 e ^{3 x}}{5 - 4 e ^{3 x}} d x

What is the derivative of x^3-6x ?
The derivative of x^3-6x is 3x^2-6
What is the first derivative of x^3-6x ?
The first derivative of x^3-6x is 3x^2-6