What is the integral of 0.0012h^2 ?

The integral of 0.0012h^2 is 0.0004h^3+C

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integral of 0.0012h^2

\int 0.0012 h^{2} d h

0.0004 h^{3} + C

Solution steps

\int 0.0012 h^{2} d h

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.0012 \cdot \int h^{2} d h

Apply the Power Rule

: \frac{h ^{3}}{3}

= 0.0012 \cdot \frac{h ^{3}}{3}

Simplify

0.0012 \cdot \frac{h ^{3}}{3} : 0.0004 h^{3}

= 0.0004 h^{3}

Add a constant to the solution

= 0.0004 h^{3} + C

x \to π lim (x + cos (x))

\int \frac{9 x ^{2} - 25}{x ^{3}} d x

\frac{8 x ^{7}}{5 y ^{4}}

\frac{1}{s \cdot ( s + 1 ) ^{2}}

9^{x}