What is the derivative of dln(x)+ax^n+be^x ?

The derivative of dln(x)+ax^n+be^x is d/x+anx^{n-1}+be^x

What is the first derivative of dln(x)+ax^n+be^x ?

The first derivative of dln(x)+ax^n+be^x is d/x+anx^{n-1}+be^x

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derivative of

d ln (x) + a x^{n} + b e^{x}

\frac{d}{x} + an x^{n - 1} + b e^{x}

Solution steps

\frac{d}{d x} (d ln (x) + a x^{n} + b e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (d ln (x)) + \frac{d}{d x} (a x^{n}) + \frac{d}{d x} (b e^{x})

\frac{d}{d x} (d ln (x)) = \frac{d}{x}

\frac{d}{d x} (a x^{n}) = an x^{n - 1}

\frac{d}{d x} (b e^{x}) = b e^{x}

= \frac{d}{x} + an x^{n - 1} + b e^{x}

\int_{0}^{7} 1 + x d x

f (x) = 4 x sin (x)

\int cos^{2} (2 x) 2 d x

x \to 0 - lim (\frac{5}{x} - \frac{5}{x})

sin (2 x + 1)

What is the derivative of dln(x)+ax^n+be^x ?
The derivative of dln(x)+ax^n+be^x is d/x+anx^{n-1}+be^x
What is the first derivative of dln(x)+ax^n+be^x ?
The first derivative of dln(x)+ax^n+be^x is d/x+anx^{n-1}+be^x