What is the derivative of (3x/(sqrt(2x+3))) ?

The derivative of (3x/(sqrt(2x+3))) is (3(x+3))/((2x+3)sqrt(2x+3))

What is the first derivative of (3x/(sqrt(2x+3))) ?

The first derivative of (3x/(sqrt(2x+3))) is (3(x+3))/((2x+3)sqrt(2x+3))

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\frac{d}{d x} (\frac{3 x}{2 x + 3})

\frac{3 ( x + 3 )}{( 2 x + 3 ) 2 x + 3}

Solution steps

\frac{d}{d x} (\frac{3 x}{2 x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{2 x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} 2 x + 3 - \frac{d}{d x} ( 2 x + 3 ) x}{( 2 x + 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (2 x + 3) = \frac{1}{2 x + 3}

= 3 \cdot \frac{1 \cdot 2 x + 3 - \frac{1}{2 x + 3} x}{( 2 x + 3 ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot 2 x + 3 - \frac{1}{2 x + 3} x}{( 2 x + 3 ) ^{2}} : \frac{3 ( x + 3 )}{( 2 x + 3 ) 2 x + 3}

= \frac{3 ( x + 3 )}{( 2 x + 3 ) 2 x + 3}

x \frac{d y}{d x} = y + (x^{2} - 4)^{2}

\frac{d}{d x} (sinh (3 x))

y = x^{3}, y = 4 x

\int - 9 x^{2} + 9 x + 2 d x

x \to 1 lim (\frac{( x ^{3} )}{x - 1})

What is the derivative of (3x/(sqrt(2x+3))) ?
The derivative of (3x/(sqrt(2x+3))) is (3(x+3))/((2x+3)sqrt(2x+3))
What is the first derivative of (3x/(sqrt(2x+3))) ?
The first derivative of (3x/(sqrt(2x+3))) is (3(x+3))/((2x+3)sqrt(2x+3))