What is the integral from 0 to 1 of (x^{10}+10^x) ?

The integral from 0 to 1 of (x^{10}+10^x) is 1/11+9/(ln(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (x^{10}+10^x)

\int_{0}^{1} (x^{10} + 1 0^{x}) d x

\frac{1}{11} + \frac{9}{ln ( 10 )}

Decimal Notation

3.99955 \dots

Solution steps

\int_{0}^{1} x^{10} + 1 0^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{10} d x + \int_{0}^{1} 1 0^{x} d x

\int_{0}^{1} x^{10} d x = \frac{1}{11}

\int_{0}^{1} 1 0^{x} d x = \frac{9}{ln ( 10 )}

= \frac{1}{11} + \frac{9}{ln ( 10 )}

y^{'} - \frac{2}{t} y = t^{2} e^{t}

\int (3 x - 4) e^{x} d x

\int sin (\frac{x}{2}) cos (\frac{x}{2}) d x

\frac{\partial}{\partial y} (4 z)

f (x) = 1 - \frac{49}{x ^{2}}

What is the integral from 0 to 1 of (x^{10}+10^x) ?
The integral from 0 to 1 of (x^{10}+10^x) is 1/11+9/(ln(10))