What is the tangent of f(x)=(3x)/(x+1),(2,2) ?

The tangent of f(x)=(3x)/(x+1),(2,2) is y= 1/3 x+4/3

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tangent of f(x)=(3x)/(x+1),(2,2)

tangent of

f (x) = \frac{3 x}{x + 1}, (2, 2)

y = \frac{1}{3} x + \frac{4}{3}

Solution steps

Find the slope of

f (x) = \frac{3 x}{x + 1} : \frac{df ( x )}{d x} = \frac{3}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{3 x}{x + 1}

(2, 2) : m = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(2, 2) : y = \frac{1}{3} x + \frac{4}{3}

y = \frac{1}{3} x + \frac{4}{3}

\int_{0}^{3} x 1 + 2 x d x

\int (y^{2} + ln (x)) d y

\int_{0}^{5} 7 x - x^{2} - 2 x d x

x \to 0 lim (sec (x))

\int \frac{x ^{4} + 2 x + 1}{x ^{3} - x ^{2} - 2 x} d x

What is the tangent of f(x)=(3x)/(x+1),(2,2) ?
The tangent of f(x)=(3x)/(x+1),(2,2) is y= 1/3 x+4/3