What is the derivative of 2x+2xln(x) ?

The derivative of 2x+2xln(x) is 2ln(x)+4

What is the first derivative of 2x+2xln(x) ?

The first derivative of 2x+2xln(x) is 2ln(x)+4

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\frac{d}{d x} (2 x + 2 x ln (x))

2 ln (x) + 4

Solution steps

\frac{d}{d x} (2 x + 2 x ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (2 x ln (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2 x ln (x)) = 2 (ln (x) + 1)

= 2 + 2 (ln (x) + 1)

Simplify

2 + 2 (ln (x) + 1) : 2 ln (x) + 4

= 2 ln (x) + 4

(4 x + 4)^{\frac{1}{3}}, at x = 2

y = \frac{- 6 x}{x ^{2} + 1}, (- 1, 3)

y^{^{''}} + 4 y^{^{'}} - 32 y = 0

\frac{d}{d x} (2 x^{3} 2 - 3 x^{2})

\frac{d}{d x} (h (g (x) k (x)))

What is the derivative of 2x+2xln(x) ?
The derivative of 2x+2xln(x) is 2ln(x)+4
What is the first derivative of 2x+2xln(x) ?
The first derivative of 2x+2xln(x) is 2ln(x)+4