What is the derivative of 4x+8+(14400/x) ?

The derivative of 4x+8+(14400/x) is -(14400)/(x^2)+4

What is the first derivative of 4x+8+(14400/x) ?

The first derivative of 4x+8+(14400/x) is -(14400)/(x^2)+4

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\frac{d}{d x} (4 x + 8 + \frac{14400}{x})

- \frac{14400}{x ^{2}} + 4

Solution steps

\frac{d}{d x} (4 x + 8 + \frac{14400}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (8) + \frac{d}{d x} (\frac{14400}{x})

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (8) = 0

\frac{d}{d x} (\frac{14400}{x}) = - \frac{14400}{x ^{2}}

= 4 + 0 - \frac{14400}{x ^{2}}

Simplify

= - \frac{14400}{x ^{2}} + 4

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What is the derivative of 4x+8+(14400/x) ?
The derivative of 4x+8+(14400/x) is -(14400)/(x^2)+4
What is the first derivative of 4x+8+(14400/x) ?
The first derivative of 4x+8+(14400/x) is -(14400)/(x^2)+4