What is the limit as x approaches 4 of (1+x/3)^2 ?

The limit as x approaches 4 of (1+x/3)^2 is 49/9

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limit as x approaches 4 of (1+x/3)^2

x \to 4 lim ((1 + \frac{x}{3})^{2})

\frac{49}{9}

Decimal Notation

5.44444 \dots

Solution steps

x \to 4 lim ((1 + \frac{x}{3})^{2})

Plug in the value

x = 4

= (1 + \frac{4}{3})^{2}

Simplify

(1 + \frac{4}{3})^{2} : \frac{49}{9}

= \frac{49}{9}

\int 3 u^{5} - 2 u^{3} d u

v^{2}

\frac{d}{d x} (\frac{4 e ^{4 x}}{e ^{8} ( e ^{16} - 1 )})

y = sin (x), at x = \frac{5 π}{3}

x \to 0 lim (\frac{5 ^{x} - 7 ^{x}}{x})

What is the limit as x approaches 4 of (1+x/3)^2 ?
The limit as x approaches 4 of (1+x/3)^2 is 49/9