What is (\partial)/(\partial y)(ln(x/y)) ?

The answer to (\partial)/(\partial y)(ln(x/y)) is -1/y

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(\partial)/(\partial y)(ln(x/y))

\frac{\partial}{\partial y} (ln (\frac{x}{y}))

- \frac{1}{y}

Solution steps

\frac{\partial}{\partial y} (ln (\frac{x}{y}))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{\frac{x}{y}} \frac{\partial}{\partial y} (\frac{x}{y})

= \frac{1}{\frac{x}{y}} \frac{\partial}{\partial y} (\frac{x}{y})

\frac{\partial}{\partial y} (\frac{x}{y}) = - \frac{x}{y ^{2}}

= \frac{1}{\frac{x}{y}} (- \frac{x}{y ^{2}})

Simplify

\frac{1}{\frac{x}{y}} (- \frac{x}{y ^{2}}) : - \frac{1}{y}

= - \frac{1}{y}

\frac{\partial}{\partial y} (x e^{y} + y e^{z} + z e^{x})

x \to 0 lim (\frac{2}{x} - \frac{2}{x})

\frac{2}{x}, \frac{2}{x ^{2}}, x = 4

f (x) = 6 sec (x) - 5 x

\frac{d}{d x} (sec (5) x^{2})

What is (\partial)/(\partial y)(ln(x/y)) ?
The answer to (\partial)/(\partial y)(ln(x/y)) is -1/y