What is the derivative of f(x)=x^{2cos(x)} ?

The derivative of f(x)=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

What is the first derivative of f(x)=x^{2cos(x)} ?

The first derivative of f(x)=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{2 c o s (x)}

2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Solution steps

\frac{d}{d x} (x^{2 c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{2 c o s (x)} = e^{2 c o s (x) l n (x)}

= \frac{d}{d x} (e^{2 c o s (x) l n (x)})

Apply the chain rule:

e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

= e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

\frac{d}{d x} (2 cos (x) ln (x)) = 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

= e^{2 c o s (x) l n (x)} \cdot 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

e^{2 c o s (x) l n (x)} = x^{2 c o s (x)}

= 2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

\frac{\partial}{\partial y} (4 x^{2 y})

\frac{d ^{2} y}{d x ^{2}} = x

f (x) = \frac{x}{x ^{2} + 1}

\frac{d}{d x} (\frac{cot ( x )}{1 + cot ( x )})

\frac{d y}{d x}, y - 5 x y^{3} + 8 = 5 sin (y^{3} + 2 x^{2})

What is the derivative of f(x)=x^{2cos(x)} ?
The derivative of f(x)=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)
What is the first derivative of f(x)=x^{2cos(x)} ?
The first derivative of f(x)=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)