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Popular >

(t+y+1)dt-dy=0

Solution

(t + y + 1) d t - d y = 0

Solution

y = - t - 2 + c_{1} e^{t}

Solution steps

(t + y + 1) d t - d y = 0

Solve linear ODE:

y = - t - 2 + c_{1} e^{t}

y = - t - 2 + c_{1} e^{t}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (t+y+1)dt-dy=0 ?
The solution for (t+y+1)dt-dy=0 is y=-t-2+c_{1}e^t