What is the derivative of (693x^{5/2})/8 ?

The derivative of (693x^{5/2})/8 is (3465x^{3/2})/(16)

What is the first derivative of (693x^{5/2})/8 ?

The first derivative of (693x^{5/2})/8 is (3465x^{3/2})/(16)

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derivative of

\frac{693 x ^{\frac{5}{2}}}{8}

\frac{3465 x ^{\frac{3}{2}}}{16}

Solution steps

\frac{d}{d x} (\frac{693 x ^{\frac{5}{2}}}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{693}{8} \frac{d}{d x} (x^{\frac{5}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{693}{8} \cdot \frac{5}{2} x^{\frac{5}{2} - 1}

Simplify

\frac{693}{8} \cdot \frac{5}{2} x^{\frac{5}{2} - 1} : \frac{3465 x ^{\frac{3}{2}}}{16}

= \frac{3465 x ^{\frac{3}{2}}}{16}

(x, y) \to (0, 0) lim (x y)

\frac{\partial}{\partial x} (e^{- (x - v t)^{2}})

\frac{\partial}{\partial x} (x cos (x) sin (x))

f (x) = cos (x) sec (x)

x^{2} - 5

What is the derivative of (693x^{5/2})/8 ?
The derivative of (693x^{5/2})/8 is (3465x^{3/2})/(16)
What is the first derivative of (693x^{5/2})/8 ?
The first derivative of (693x^{5/2})/8 is (3465x^{3/2})/(16)