What is the derivative of tan(5x+5) ?

The derivative of tan(5x+5) is sec^2(5x+5)*5

What is the first derivative of tan(5x+5) ?

The first derivative of tan(5x+5) is sec^2(5x+5)*5

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\frac{d}{d x} (tan (5 x + 5))

sec^{2} (5 x + 5) \cdot 5

Solution steps

\frac{d}{d x} (tan (5 x + 5))

Apply the chain rule:

sec^{2} (5 x + 5) \frac{d}{d x} (5 x + 5)

= sec^{2} (5 x + 5) \frac{d}{d x} (5 x + 5)

\frac{d}{d x} (5 x + 5) = 5

= sec^{2} (5 x + 5) \cdot 5

\int_{0}^{3} \frac{x}{9 - x ^{2}} d x

\int 45 t - \frac{21}{t} d t

\frac{d}{d x} (\frac{2}{x ^{3} + 1})

\frac{d}{d x} (\frac{- 5}{x ^{5}})

\int \frac{x ^{2}}{csc ( x )} d x

What is the derivative of tan(5x+5) ?
The derivative of tan(5x+5) is sec^2(5x+5)*5
What is the first derivative of tan(5x+5) ?
The first derivative of tan(5x+5) is sec^2(5x+5)*5