What is the derivative of 8e^{-2x} ?

The derivative of 8e^{-2x} is -16e^{-2x}

What is the first derivative of 8e^{-2x} ?

The first derivative of 8e^{-2x} is -16e^{-2x}

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derivative of

8 e^{- 2 x}

- 16 e^{- 2 x}

Solution steps

\frac{d}{d x} (8 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= 8 e^{- 2 x} (- 2)

Simplify

= - 16 e^{- 2 x}

f (x) = x - 2 sin (x)

\int x^{2} + 6 x + 45 d x

x \to 0 lim (\frac{2}{x ^{6}})

n = 1 \sum \infty \frac{4 ^{n}}{n ^{2}}

\frac{1}{1 + x ^{2}}

What is the derivative of 8e^{-2x} ?
The derivative of 8e^{-2x} is -16e^{-2x}
What is the first derivative of 8e^{-2x} ?
The first derivative of 8e^{-2x} is -16e^{-2x}