What is the integral from 1 to 7 of sqrt(x-1) ?

The integral from 1 to 7 of sqrt(x-1) is 4sqrt(6)

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integral from 1 to 7 of sqrt(x-1)

\int_{1}^{7} x - 1 d x

46

Decimal

9.79795 \dots

Solution steps

\int_{1}^{7} x - 1 d x

Apply u-substitution

: \int_{0}^{6} u d u

= \int_{0}^{6} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{6}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{6}

Compute the boundaries:

46

= 46

\int \frac{ln ( ln ( 3 x ) )}{3 x} d x

x \to 3 lim (5 x^{3} - 3 x + x - 6)

\frac{\partial}{\partial x} (am x^{b} m y^{1 - b})

\frac{d}{d x} (arccos (x^{2}))

\int_{0}^{1} \frac{2 x}{e ^{2 x}} d x

What is the integral from 1 to 7 of sqrt(x-1) ?
The integral from 1 to 7 of sqrt(x-1) is 4sqrt(6)