What is laplacetransform 2*sin(3t) ?

The answer to laplacetransform 2*sin(3t) is 6/(s^2+9)

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laplacetransform 2*sin(3t)

laplace transform

2 \cdot sin (3 t)

\frac{6}{s ^{2} + 9}

Solution steps

L {2 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 2 \cdot \frac{3}{s ^{2} + 9}

Refine

2 \frac{3}{s ^{2} + 9} : \frac{6}{s ^{2} + 9}

= \frac{6}{s ^{2} + 9}

y = e^{3 x}, y = e^{- 3 x}, x = - 1

\frac{d}{d x} (\frac{e ^{\frac{7 x}{4}}}{1 - 9 x ^{2}})

\int_{0}^{2} - 6 x^{3} x^{2} + 4 d x

\frac{d}{d x} (1 + x + 5 x^{2})

\int_{- 2}^{1} 2 - x^{2} - x d x

What is laplacetransform 2*sin(3t) ?
The answer to laplacetransform 2*sin(3t) is 6/(s^2+9)