What is the solution for (dy)/(dx)= y/(x^2),y(1)=1 ?

The solution for (dy)/(dx)= y/(x^2),y(1)=1 is y=e^{-1/x+1}

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(dy)/(dx)= y/(x^2),y(1)=1

\frac{d y}{d x} = \frac{y}{x ^{2}}, y (1) = 1

y = e^{- \frac{1}{x} + 1}

Solution steps

\frac{d y}{d x} = \frac{y}{x ^{2}}

Solve separable ODE:

y = e^{- \frac{1}{x} + 1}

y = e^{- \frac{1}{x} + 1}

x \to 1 + lim (\frac{4}{x ^{(1 - x)}})

\frac{d}{d x} (sec^{2} (x) - 1)

\int_{0}^{\frac{π}{2}} \frac{1}{x ^{2} + 2} d x

x \to \infty lim (\frac{x ^{5}}{x ^{10} + 9})

f (x) = x^{2} sin (x) + 2 x cos (x)

What is the solution for (dy)/(dx)= y/(x^2),y(1)=1 ?
The solution for (dy)/(dx)= y/(x^2),y(1)=1 is y=e^{-1/x+1}