What is the sum from n=0 to infinity}(1-10^{42 of)^n ?

The sum from n=0 to infinity}(1-10^{42 of)^n is diverges

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sum from n=0 to infinity}(1-10^{42 of)^n

n = 0 \sum \infty (1 - 1 0^{42})^{n}

diverges

Solution steps

n = 0 \sum \infty (1 - 1 0^{42})^{n}

(1 - 1 0^{42})^{n} = 1.0 E 4 2^{n} (- 1)^{n}

= n = 0 \sum \infty 1.0 E 4 2^{n} (- 1)^{n}

Apply Series Ratio Test:

diverges

= diverges

\frac{d}{d x} (ln (x) sin (x))

\frac{d ^{2} y}{d x ^{2}} = 3 e^{- x}, y (0) = 1, y^{^{'}} (0) = 4

\int 1 \frac{1}{x ^{2}} d x

(\frac{( x + 3 )}{x - 1})^{2}

y^{^{'}} - 2 x = 4 x^{3}, y (0) = 1

What is the sum from n=0 to infinity}(1-10^{42 of)^n ?
The sum from n=0 to infinity}(1-10^{42 of)^n is diverges