What is (\partial)/(\partial x)(y(-3-x)) ?

The answer to (\partial)/(\partial x)(y(-3-x)) is -y

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(\partial)/(\partial x)(y(-3-x))

\frac{\partial}{\partial x} (y (- 3 - x))

- y

Solution steps

\frac{\partial}{\partial x} (y (- 3 - x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (- 3 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (- \frac{\partial}{\partial x} (3) - \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (3) = 0

\frac{\partial}{\partial x} (x) = 1

= y (- 0 - 1)

Simplify

= - y

\int cos (x) 7 5 + sin (x) d x

\frac{\partial}{\partial x} (x y - x^{2} y)

\frac{\partial}{\partial x} (2 x z^{3} e^{y^{2}})

\int \frac{1}{1 + z ^{2}} d z

f (x) = 4 (4 e^{x} - 25)^{7}

What is (\partial)/(\partial x)(y(-3-x)) ?
The answer to (\partial)/(\partial x)(y(-3-x)) is -y