What is the integral of 15+0.55x ?

The integral of 15+0.55x is 0.90909…(15+0.55x)^2+C

Popular >

integral of 15+0.55x

\int 15 + 0.55 x d x

0.90909 \dots (15 + 0.55 x)^{2} + C

Solution steps

\int 15 + 0.55 x d x

Apply u-substitution

: \int \frac{u}{0.55} d u

= \int \frac{u}{0.55} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{0.55} \cdot \int u d u

Simplify

= 1.81818 \dots \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= 1.81818 \dots \cdot \frac{u ^{2}}{2}

Substitute back

u = 15 + 0.55 x

= 1.81818 \dots \cdot \frac{( 15 + 0.55 x ) ^{2}}{2}

Simplify

1.81818 \dots \cdot \frac{( 15 + 0.55 x ) ^{2}}{2} : 0.90909 \dots (15 + 0.55 x)^{2}

= 0.90909 \dots (15 + 0.55 x)^{2}

Add a constant to the solution

= 0.90909 \dots (15 + 0.55 x)^{2} + C

\int x^{- \frac{5}{2}} d x

\frac{2 - 3 s}{s ^{2} - 3}

y = (∣ x - 2 ∣)^{3}, y = 8 - 4 x

x \to 0 lim (\frac{( 2 ^{x} - 1 )}{x})

\int \frac{1}{y ^{2} - y ^{3}} d y

What is the integral of 15+0.55x ?
The integral of 15+0.55x is 0.90909…(15+0.55x)^2+C