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Popular >

y^'+0.564y^2=0

Solution

y^{^{'}} + 0.564 y^{2} = 0

Solution

y = - \frac{250}{- 141 t + c _{1}}

Solution steps

y^{'} (t) + 0.564 y^{2} = 0

Solve separable ODE:

y = - \frac{250}{- 141 t + c _{1}}

y = - \frac{250}{- 141 t + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+0.564y^2=0 ?
The solution for y^'+0.564y^2=0 is y=-(250)/(-141t+c_{1)}