What is the derivative of 3x^9 ?

The derivative of 3x^9 is 27x^8

What is the first derivative of 3x^9 ?

The first derivative of 3x^9 is 27x^8

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\frac{d}{d x} (3 x^{9})

27 x^{8}

Solution steps

\frac{d}{d x} (3 x^{9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{9})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 9 x^{9 - 1}

Simplify

= 27 x^{8}

\frac{d}{d x} ((ln (x))^{l n (x)})

\int \frac{1}{12 x ^{5}} d x

x \to - \infty + lim (- 5 x^{3})

\frac{d}{d x} (\frac{x ^{6}}{4 - x ^{5}})

\frac{d}{d x} (3 x^{8})