What is the integral from 0 to 2 of y^{7/2} ?

The integral from 0 to 2 of y^{7/2} is (32*2^{1/2})/9

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integral from 0 to 2 of y^{7/2}

\int_{0}^{2} y^{\frac{7}{2}} d y

\frac{32 \cdot 2 ^{\frac{1}{2}}}{9}

Decimal

5.02831 \dots

Solution steps

\int_{0}^{2} y^{\frac{7}{2}} d y

Apply the Power Rule

: [\frac{2}{9} y^{\frac{9}{2}}]_{0}^{2}

= [\frac{2}{9} y^{\frac{9}{2}}]_{0}^{2}

Compute the boundaries:

\frac{32 \cdot 2 ^{\frac{1}{2}}}{9}

= \frac{32 \cdot 2 ^{\frac{1}{2}}}{9}

\frac{d}{d x} (\frac{5 x}{x})

f (t) = t e^{2 t}

\int - x^{2} - 3 x d x

f (x) = 4 x^{\frac{5}{4}} + 10 x^{\frac{3}{2}} + 3 x

\int x^{5} x^{6} - 1 d x

What is the integral from 0 to 2 of y^{7/2} ?
The integral from 0 to 2 of y^{7/2} is (32*2^{1/2})/9