What is the derivative of e^{2e^x} ?

The derivative of e^{2e^x} is 2e^{2e^x+x}

What is the first derivative of e^{2e^x} ?

The first derivative of e^{2e^x} is 2e^{2e^x+x}

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\frac{d}{d x} (e^{2 e^{x}})

2 e^{2 e^{x} + x}

Solution steps

\frac{d}{d x} (e^{2 e^{x}})

Apply the chain rule:

e^{2 e^{x}} \frac{d}{d x} (2 e^{x})

= e^{2 e^{x}} \frac{d}{d x} (2 e^{x})

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= e^{2 e^{x}} \cdot 2 e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{2 e^{x}} e^{x} = e^{2 e^{x} + x}

= 2 e^{2 e^{x} + x}

\int ((csc (y))^{2} - sec (y) tan (y)) d y

\int_{- π}^{π} x^{2} sin (x) d x

(4 x y + 3 y^{2} - x) d x + x (x + 2 y) d y = 0

\int 2 x e^{x^{2}} d x

\frac{1}{( 1 + x ) ^{2}}, 0

What is the derivative of e^{2e^x} ?
The derivative of e^{2e^x} is 2e^{2e^x+x}
What is the first derivative of e^{2e^x} ?
The first derivative of e^{2e^x} is 2e^{2e^x+x}