What is the derivative of x^4y^3 ?

The derivative of x^4y^3 is 4x^3y^3+3y^2(dy)/(dx)x^4

What is the first derivative of x^4y^3 ?

The first derivative of x^4y^3 is 4x^3y^3+3y^2(dy)/(dx)x^4

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\frac{d}{d x} (x^{4} y^{3})

4 x^{3} y^{3} + 3 y^{2} \frac{d y}{d x} x^{4}

Solution steps

\frac{d}{d x} (x^{4} y^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{4}, g = y^{3}

= \frac{d}{d x} (x^{4}) y^{3} + \frac{d}{d x} (y^{3}) x^{4}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (y^{3}) = 3 y^{2} \frac{d y}{d x}

= 4 x^{3} y^{3} + 3 y^{2} \frac{d y}{d x} x^{4}

\int sin (π) t d t

x^{2} y \cdot \frac{d y}{d x} - 9 = 0

x^{^{''}} - x^{^{'}} + x = 0

x = y^{2} - 5, x = 3 - y^{2}

arcsin (ln (x))

What is the derivative of x^4y^3 ?
The derivative of x^4y^3 is 4x^3y^3+3y^2(dy)/(dx)x^4
What is the first derivative of x^4y^3 ?
The first derivative of x^4y^3 is 4x^3y^3+3y^2(dy)/(dx)x^4