What is the solution for (dy)/(dx)-2ytan(x)=y^2tan^2(x) ?

The solution for (dy)/(dx)-2ytan(x)=y^2tan^2(x) is y=(3sec^2(x))/(-tan^3(x)+c_{1)}

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(dy)/(dx)-2ytan(x)=y^2tan^2(x)

\frac{d y}{d x} - 2 y tan (x) = y^{2} tan^{2} (x)

y = \frac{3 sec ^{2} ( x )}{- tan ^{3} ( x ) + c _{1}}

Solution steps

\frac{d y}{d x} - 2 y tan (x) = y^{2} tan^{2} (x)

Solve Bernoulli ODE:

y = \frac{3 sec ^{2} ( x )}{- tan ^{3} ( x ) + c _{1}}

y = \frac{3 sec ^{2} ( x )}{- tan ^{3} ( x ) + c _{1}}

\int \frac{x ^{2}}{x - 6} d x

f (x) = \frac{x ^{2}}{e ^{x}}

y = \frac{2}{ln ( x )}

f (x) = \frac{1}{x ^{7}}

f (t) = 2 t^{2}

What is the solution for (dy)/(dx)-2ytan(x)=y^2tan^2(x) ?
The solution for (dy)/(dx)-2ytan(x)=y^2tan^2(x) is y=(3sec^2(x))/(-tan^3(x)+c_{1)}