What is (\partial)/(\partial x)(e^{x^2-y^2}) ?

The answer to (\partial)/(\partial x)(e^{x^2-y^2}) is e^{x^2-y^2}*2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(e^{x^2-y^2})

\frac{\partial}{\partial x} (e^{x^{2} - y^{2}})

e^{x^{2} - y^{2}} \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (e^{x^{2} - y^{2}})

Treat

y

as a constant

Apply the chain rule:

e^{x^{2} - y^{2}} \frac{\partial}{\partial x} (x^{2} - y^{2})

= e^{x^{2} - y^{2}} \frac{\partial}{\partial x} (x^{2} - y^{2})

\frac{\partial}{\partial x} (x^{2} - y^{2}) = 2 x

= e^{x^{2} - y^{2}} \cdot 2 x

y^{^{'}} + 2 x^{2} y = x^{2}

\int \frac{2 - 2 x}{1 - x} d x

\frac{d y}{d x} + \frac{y}{x} = 2 x^{8} y^{2}

\frac{\partial}{\partial x} (arctan (9 x))

y = (4 x^{2} + 3) (2 x - 3)

What is (\partial)/(\partial x)(e^{x^2-y^2}) ?
The answer to (\partial)/(\partial x)(e^{x^2-y^2}) is e^{x^2-y^2}*2x