What is the sum from n=0 to infinity of sin^2(n) ?

The sum from n=0 to infinity of sin^2(n) is diverges

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sum from n=0 to infinity of sin^2(n)

n = 0 \sum \infty sin^{2} (n)

diverges

Solution steps

n = 0 \sum \infty sin^{2} (n)

Apply Series Divergence Test:

diverges

= diverges

\int \frac{1}{x ^{2} + 4 x} d x

\frac{3 x}{x - 9}

ln (3 x)

(x^{3} - 4 x)^{10}

\int \frac{1}{x ^{2} + 7 x + 12} d x

What is the sum from n=0 to infinity of sin^2(n) ?
The sum from n=0 to infinity of sin^2(n) is diverges