What is (\partial)/(\partial x)(2x^2+9y^2) ?

The answer to (\partial)/(\partial x)(2x^2+9y^2) is 4x

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(\partial)/(\partial x)(2x^2+9y^2)

\frac{\partial}{\partial x} (2 x^{2} + 9 y^{2})

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 9 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (9 y^{2})

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (9 y^{2}) = 0

= 4 x + 0

Simplify

= 4 x

\int 2 e^{3 x + e^{3 x}} d x

\frac{d}{d t} (2 e^{t} cos (t))

\frac{d P}{d t} + 2 tP = P + 6 t - 3

\int \frac{2 x + 5}{16 - 6 x - x ^{2}} d x

\int x^{3} x^{2} + 31 d x

What is (\partial)/(\partial x)(2x^2+9y^2) ?
The answer to (\partial)/(\partial x)(2x^2+9y^2) is 4x