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Popular >

y^'=(y(x-y))/(x^2)

Solution

y^{^{'}} = \frac{y ( x - y )}{x ^{2}}

Solution

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

y^{'} (x) = \frac{y ( x - y )}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

Graph

Popular Examples

\frac{d y}{d x} = 2 + 3 y

limit as x approaches 0 of ln(x^2)(-2)

x \to 0 lim (ln (x^{2}) (- 2))

(\partial)/(\partial x)(x^2+3xy^2+2y)

\frac{\partial}{\partial x} (x^{2} + 3 x y^{2} + 2 y)

y^{''}+4y=2cos(2t)

y^{^{''}} + 4 y = 2 cos (2 t)

integral from 1 to b of (2x)/(x^2+4)

\int_{1}^{b} \frac{2 x}{x ^{2} + 4} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y(x-y))/(x^2) ?
The solution for y^'=(y(x-y))/(x^2) is y= x/(ln(x)+c_{1)}