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Popular >

x^2y+y^'=-3x^2

Solution

x^{2} y + y^{^{'}} = - 3 x^{2}

Solution

y = e^{- \frac{x ^{3}}{3} + c_{1}} - 3

Solution steps

x^{2} y + y^{'} (x) = - 3 x^{2}

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + c_{1}} - 3

y = e^{- \frac{x ^{3}}{3} + c_{1}} - 3

Graph

Popular Examples

tangent of f(x)=sqrt(1+4x),\at x=2 tangent of

f (x) = 1 + 4 x, at x = 2

limit as x approaches c of x^3+4x^2-3

x \to c lim (x^{3} + 4 x^{2} - 3)

integral from 0 to 1 of (3+2x^2)

\int_{0}^{1} (3 + 2 x^{2}) d x

derivative of (-x^2-7)/((x^2-7)^2)derivative of

\frac{- x ^{2} - 7}{( x ^{2} - 7 ) ^{2}}

integral of (3x^2)/((2x^3-4)^2)

\int \frac{3 x ^{2}}{( 2 x ^{3} - 4 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for x^2y+y^'=-3x^2 ?
The solution for x^2y+y^'=-3x^2 is y=e^{-(x^3)/3+c_{1}}-3