What is the limit as x approaches 0 of ((sin(4x)))/(2x) ?

The limit as x approaches 0 of ((sin(4x)))/(2x) is 2

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limit as x approaches 0 of ((sin(4x)))/(2x)

x \to 0 lim (\frac{( sin ( 4 x ) )}{2 x})

2

Solution steps

x \to 0 lim (\frac{sin ( 4 x )}{2 x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{2} \cdot x \to 0 lim (\frac{sin ( 4 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( 4 x ) \cdot 4}{1})

= \frac{1}{2} \cdot x \to 0 lim (\frac{cos ( 4 x ) \cdot 4}{1})

Plug in the value

x = 0

= \frac{1}{2} \cdot \frac{cos ( 4 \cdot 0 ) \cdot 4}{1}

Simplify

\frac{1}{2} \cdot \frac{cos ( 4 \cdot 0 ) \cdot 4}{1} : 2

= 2

\int 2 sin^{3} (x) cos^{5} (x) d x

\frac{\partial}{\partial y} (x y cos (x y) + sin (x y))

f (x) = arctan (3 x)

\frac{s + 1}{s ^{2} + 4}

\frac{( x ^{2} + 2 ) ^{\frac{3}{2}}}{3}

What is the limit as x approaches 0 of ((sin(4x)))/(2x) ?
The limit as x approaches 0 of ((sin(4x)))/(2x) is 2