What is the derivative of 1-e^{-x} ?

The derivative of 1-e^{-x} is e^{-x}

What is the first derivative of 1-e^{-x} ?

The first derivative of 1-e^{-x} is e^{-x}

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derivative of

1 - e^{- x}

e^{- x}

Solution steps

\frac{d}{d x} (1 - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 0 - (- e^{- x})

Simplify

= e^{- x}

\int 1 - sin (x) d x

x \to 0 lim (\frac{x 7 ^{x}}{7 x - 1})

y = x^{2}, y = 1

\int \frac{7 x ^{2} + 3 x}{x ^{3} + 4 x ^{2} + 3 x + 12} d x

\frac{d}{d x} (\frac{( x ^{2} + x ) ( x ^{2} - x + 1 )}{x ^{4}})

What is the derivative of 1-e^{-x} ?
The derivative of 1-e^{-x} is e^{-x}
What is the first derivative of 1-e^{-x} ?
The first derivative of 1-e^{-x} is e^{-x}