What is the derivative of 2x^2+3x-2 ?

The derivative of 2x^2+3x-2 is 4x+3

What is the first derivative of 2x^2+3x-2 ?

The first derivative of 2x^2+3x-2 is 4x+3

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\frac{d}{d x} (2 x^{2} + 3 x - 2)

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 4 x + 3 - 0

Simplify

= 4 x + 3

\frac{d}{d x} (5 x^{e})

\int 3 x e^{5 x} d x

\frac{d}{d x} (\frac{( x ^{2} - 4 x )}{x + 1})

\frac{d}{d x} (\frac{sin ( x ) + cos ( x )}{cos ( x )})

\frac{\partial}{\partial x} (sin (y^{2}) + 6 e^{x})

What is the derivative of 2x^2+3x-2 ?
The derivative of 2x^2+3x-2 is 4x+3
What is the first derivative of 2x^2+3x-2 ?
The first derivative of 2x^2+3x-2 is 4x+3