What is the derivative of 2x^4+x^2-x^2+4 ?

The derivative of 2x^4+x^2-x^2+4 is 8x^3

What is the first derivative of 2x^4+x^2-x^2+4 ?

The first derivative of 2x^4+x^2-x^2+4 is 8x^3

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\frac{d}{d x} (2 x^{4} + x^{2} - x^{2} + 4)

8 x^{3}

Solution steps

\frac{d}{d x} (2 x^{4} + x^{2} - x^{2} + 4)

Simplify

2 x^{4} + x^{2} - x^{2} + 4 : 2 x^{4} + 4

= \frac{d}{d x} (2 x^{4} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (4) = 0

= 8 x^{3} + 0

Simplify

= 8 x^{3}

\frac{\partial}{\partial x} (y \cdot e^{x y})

\frac{s + 1}{s ^{2} + 2}

x^{2} - 9 x

\frac{d}{d x} (- x sin (x) - cos (x))

(y e^{4 x y} + x) d x + (x e^{4 x y}) d y = 0

What is the derivative of 2x^4+x^2-x^2+4 ?
The derivative of 2x^4+x^2-x^2+4 is 8x^3
What is the first derivative of 2x^4+x^2-x^2+4 ?
The first derivative of 2x^4+x^2-x^2+4 is 8x^3