What is the derivative of (x-4^8(2x+3)^6) ?

The derivative of (x-4^8(2x+3)^6) is 8(x-4)^7(2x+3)^6+12(2x+3)^5(x-4)^8

What is the first derivative of (x-4^8(2x+3)^6) ?

The first derivative of (x-4^8(2x+3)^6) is 8(x-4)^7(2x+3)^6+12(2x+3)^5(x-4)^8

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\frac{d}{d x} ((x - 4)^{8} (2 x + 3)^{6})

8 (x - 4)^{7} (2 x + 3)^{6} + 12 (2 x + 3)^{5} (x - 4)^{8}

Solution steps

\frac{d}{d x} ((x - 4)^{8} (2 x + 3)^{6})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (x - 4)^{8}, g = (2 x + 3)^{6}

= \frac{d}{d x} ((x - 4)^{8}) (2 x + 3)^{6} + \frac{d}{d x} ((2 x + 3)^{6}) (x - 4)^{8}

\frac{d}{d x} ((x - 4)^{8}) = 8 (x - 4)^{7}

\frac{d}{d x} ((2 x + 3)^{6}) = 12 (2 x + 3)^{5}

= 8 (x - 4)^{7} (2 x + 3)^{6} + 12 (2 x + 3)^{5} (x - 4)^{8}

y^{^{''}} - 8 y^{^{'}} + 17 y = 0, y (0) = 4

1 - cos (θ)

x \to - 1 lim (- x^{5} - 3 x^{4})

\int 16 x - x^{2} d x

\int_{- 1}^{3} x^{5} d x

What is the derivative of (x-4^8(2x+3)^6) ?
The derivative of (x-4^8(2x+3)^6) is 8(x-4)^7(2x+3)^6+12(2x+3)^5(x-4)^8
What is the first derivative of (x-4^8(2x+3)^6) ?
The first derivative of (x-4^8(2x+3)^6) is 8(x-4)^7(2x+3)^6+12(2x+3)^5(x-4)^8