What is the derivative of x^{-4}+cos(x) ?

The derivative of x^{-4}+cos(x) is -4/(x^5)-sin(x)

What is the first derivative of x^{-4}+cos(x) ?

The first derivative of x^{-4}+cos(x) is -4/(x^5)-sin(x)

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\frac{d}{d x} (x^{- 4} + cos (x))

- \frac{4}{x ^{5}} - sin (x)

Solution steps

\frac{d}{d x} (x^{- 4} + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{- 4}) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (x^{- 4}) = - \frac{4}{x ^{5}}

\frac{d}{d x} (cos (x)) = - sin (x)

= - \frac{4}{x ^{5}} - sin (x)

f (x) = \frac{cos ( t )}{t ^{7}}

x \to - 3 lim (2 x + 1)

\int \frac{1}{x ^{2} + 6 x + 10} d x

(10 + x^{6}) \frac{d y}{d x} = \frac{x ^{5}}{y}

x \to 2 lim (x (x + 1) (x + 2))

What is the derivative of x^{-4}+cos(x) ?
The derivative of x^{-4}+cos(x) is -4/(x^5)-sin(x)
What is the first derivative of x^{-4}+cos(x) ?
The first derivative of x^{-4}+cos(x) is -4/(x^5)-sin(x)