What is the tangent of 4q+1,\at x=10 ?

The tangent of 4q+1,\at x=10 is y=4 d/(d10)(q(10))x+4q(10)+1-40 d/(d10)(q(10))

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tangent of 4q+1,\at x=10

tangent of

4 q + 1, at x = 10

y = 4 \frac{d}{d 10} (q (10)) x + 4 q (10) + 1 - 40 \frac{d}{d 10} (q (10))

Solution steps

Find the tangent point:

(10, 4 q (10) + 1)

Find the slope of

y = 4 q + 1 : \frac{d y}{d x} = 4 \frac{d q}{d x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 \frac{d}{d 10} (q (10))

Find the line with slope m=

4 \frac{d}{d 10} (q (10))

and passing through

(10, 4 q (10) + 1) : y = 4 \frac{d}{d 10} (q (10)) x + 4 q (10) + 1 - 40 \frac{d}{d 10} (q (10))

y = 4 \frac{d}{d 10} (q (10)) x + 4 q (10) + 1 - 40 \frac{d}{d 10} (q (10))

5 x^{2} \frac{d ^{2} y}{d x ^{2}} - 16 x \frac{d y}{d x} + 4 y = 0

\int_{0}^{5} x 5 - x d x

x^{2} y^{^{''}} + 2 x y^{^{'}} - 6 y = 0, y (1) = 0

\frac{d}{d x} (e^{5 x + 2 x^{2}})

\frac{d}{d x} (\frac{1}{2} arctan (\frac{x + 1}{2}))

What is the tangent of 4q+1,\at x=10 ?
The tangent of 4q+1,\at x=10 is y=4 d/(d10)(q(10))x+4q(10)+1-40 d/(d10)(q(10))