What is the integral of (x^{1/3}) ?

The integral of (x^{1/3}) is 3/4 x^{4/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^{1/3})

\int (x^{\frac{1}{3}}) d x

\frac{3}{4} x^{\frac{4}{3}} + C

Solution steps

\int x^{\frac{1}{3}} d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= \frac{3}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + C

\int 5 x^{7} e^{- x^{4}} d x

f (x) = x (x + 3)^{3}

\int (tan (x) - 1)^{2} d x

\frac{d}{d x} (\frac{1 + x ^{2}}{1 + y ^{2}})

x \to 0 lim (\frac{e x}{x})