What is the limit as x approaches 2-of ln|x-2| ?

The limit as x approaches 2-of ln|x-2| is -infinity

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limit as x approaches 2-of ln|x-2|

x \to 2 - lim (ln ∣ x - 2 ∣)

- \infty

Solution steps

x \to 2 - lim (ln ∣ x - 2 ∣)

x - 2

is negative when

x \to 2 -

. Therefore

∣ x - 2 ∣ = - x + 2

= x \to 2 - lim (ln (- x + 2))

Apply the Limit Chain Rule:

- \infty

= - \infty

\int \frac{1}{x ^{2} - y ^{2}} d y

f (x) = \frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

x \to 0 - lim (e^{\frac{5}{x}})

x \to \infty lim (x^{- 4})

\frac{\partial}{\partial y} (x^{3} + y^{2})

What is the limit as x approaches 2-of ln|x-2| ?
The limit as x approaches 2-of ln|x-2| is -infinity