What is the derivative of-xe^x ?

The derivative of-xe^x is -e^x-e^xx

What is the first derivative of-xe^x ?

The first derivative of-xe^x is -e^x-e^xx

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derivative of

- x e^{x}

- e^{x} - e^{x} x

Solution steps

\frac{d}{d x} (- x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= - (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= - (1 \cdot e^{x} + e^{x} x)

Simplify

= - e^{x} - e^{x} x

y^{2} = x + 4, y^{2} = 2 - x

\int \frac{9 w ^{8} - 5 w ^{5} + 3 w ^{2} - 16}{8 w ^{4}} d w

\int - 5 x^{- 8} d x

\frac{d}{d x} (- \frac{x ^{3} + 8 x ^{2} + 19 x + 12}{( x + 20 )})

\frac{d}{d x} (a \cdot x + b)

What is the derivative of-xe^x ?
The derivative of-xe^x is -e^x-e^xx
What is the first derivative of-xe^x ?
The first derivative of-xe^x is -e^x-e^xx