What is the limit as x approaches-2+of (-8x)/(x+2) ?

The limit as x approaches-2+of (-8x)/(x+2) is infinity

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limit as x approaches-2+of (-8x)/(x+2)

x \to - 2 + lim (\frac{- 8 x}{x + 2})

\infty

Solution steps

x \to - 2 + lim (\frac{- 8 x}{x + 2})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - 8 \cdot x \to - 2 + lim (\frac{x}{x + 2})

Divide by highest denominator power:

\frac{1}{1 + \frac{2}{x}}

= - 8 \cdot x \to - 2 + lim (\frac{1}{1 + \frac{2}{x}})

For

x

approaching

- 2

from the right

, x > - 2 \Rightarrow 1 + \frac{2}{x} < 0

The denominator is a negative quantity approaching 0 from the left

= - 8 (- \infty)

Apply Infinity Property:

- c \cdot (- \infty) = \infty

= \infty

\int 2 cos (d) x d x

\frac{1}{s ( s + 6 ) ( s + 2 )}

x \to + 6 - lim (\frac{1}{x - 6})

y^{^{'}} = 3 y^{2} sin (x)

\frac{d y}{d x} = 10 x + y - 10

What is the limit as x approaches-2+of (-8x)/(x+2) ?
The limit as x approaches-2+of (-8x)/(x+2) is infinity