What is the integral of 1/(sqrt(1-u^2)) ?

The integral of 1/(sqrt(1-u^2)) is arcsin(u)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(sqrt(1-u^2))

\int \frac{1}{1 - u ^{2}} d u

arcsin (u) + C

Solution steps

\int \frac{1}{1 - u ^{2}} d u

Use the common integral:

\int \frac{1}{1 - u ^{2}} d u = arcsin (u)

= arcsin (u)

Add a constant to the solution

= arcsin (u) + C

\frac{A}{y ^{9}} + B e^{y}

\int \frac{3}{x ^{2} + 9} d x

\int \frac{t}{1} d t

\int 4 tan (4 x) d x

\frac{d}{d x} (x 6 - x)

What is the integral of 1/(sqrt(1-u^2)) ?
The integral of 1/(sqrt(1-u^2)) is arcsin(u)+C