What is the solution for y^'=y*k(100-y) ?

The solution for y^'=y*k(100-y) is y=(100)/(e^{-100kt+c_{1)}+1}

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y^'=y*k(100-y)

y^{^{'}} = y \cdot k (100 - y)

y = \frac{100}{e ^{- 100 k t + c_{1}} + 1}

Solution steps

y^{'} (t) = y \cdot k (100 - y)

Solve Bernoulli ODE:

y = \frac{100}{e ^{- 100 k t + c_{1}} + 1}

y = \frac{100}{e ^{- 100 k t + c_{1}} + 1}

\frac{d}{d x} (- \frac{x ^{6}}{1 + x ^{12}})

\int \frac{x}{( x + 3 ) ^{2}} d x

cot (x) y^{^{'}} = y

\frac{\partial}{\partial y} (e^{x^{2}} + y^{2})

x \to 3 + lim (\frac{x ^{2}}{x - 3})

What is the solution for y^'=y*k(100-y) ?
The solution for y^'=y*k(100-y) is y=(100)/(e^{-100kt+c_{1)}+1}