What is the integral from 0 to 3 of 1/(xsqrt(x)) ?

The integral from 0 to 3 of 1/(xsqrt(x)) is diverges

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integral from 0 to 3 of 1/(xsqrt(x))

\int_{0}^{3} \frac{1}{x x} d x

diverges

Solution steps

\int_{0}^{3} \frac{1}{x x} d x

Simplify

x x : x^{\frac{3}{2}}

= \int_{0}^{3} \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: [- \frac{2}{x}]_{0}^{3}

= [- \frac{2}{x}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

x \to 0 lim (- sin (x) + x)

f (x) = x (8 - x)^{3}

(x - 9) y^{^{'}} + y = x^{2} - 1

\frac{d}{d x} (lo g_{5} (3 x^{2} + 4 x))

(\frac{8 x}{8 x + 6})^{7 x}

What is the integral from 0 to 3 of 1/(xsqrt(x)) ?
The integral from 0 to 3 of 1/(xsqrt(x)) is diverges