What is the derivative of x^2+x^2ln(x) ?

The derivative of x^2+x^2ln(x) is 3x+2xln(x)

What is the first derivative of x^2+x^2ln(x) ?

The first derivative of x^2+x^2ln(x) is 3x+2xln(x)

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\frac{d}{d x} (x^{2} + x^{2} ln (x))

3 x + 2 x ln (x)

Solution steps

\frac{d}{d x} (x^{2} + x^{2} ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x^{2} ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{2} ln (x)) = 2 x ln (x) + x

= 2 x + 2 x ln (x) + x

Simplify

= 3 x + 2 x ln (x)

\frac{d y}{d t} = t^{4} y

x^{4}, 1

- \frac{2 x}{x ^{2} + 1}

\int_{0}^{l n (2)} s e^{s} d s

\frac{\partial}{\partial x} (\frac{2}{2 x + y})

What is the derivative of x^2+x^2ln(x) ?
The derivative of x^2+x^2ln(x) is 3x+2xln(x)
What is the first derivative of x^2+x^2ln(x) ?
The first derivative of x^2+x^2ln(x) is 3x+2xln(x)