What is the limit as x approaches 0+of sin(x) ?

The limit as x approaches 0+of sin(x) is 0

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limit as x approaches 0+of sin(x)

x \to 0 + lim (sin (x))

0

Solution steps

x \to 0 + lim (sin (x))

Plug in the value

x = 0

= sin (0)

Use the following trivial identity:

sin (0) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

\int (a x^{3} - b x^{2} - c x + d) d x

\int_{- 2}^{4} ∣ x ∣ d x

\frac{d y}{d x} = x e^{y}

y^{^{''}} - 4 y^{^{'}} + \frac{25}{4} y = 10 cos (8 x)

f (x) = \frac{2 + x + 8 x ^{3}}{x ^{4}}

What is the limit as x approaches 0+of sin(x) ?
The limit as x approaches 0+of sin(x) is 0