What is the tangent of f(x)=sqrt(5+8x),\at x=0 ?

The tangent of f(x)=sqrt(5+8x),\at x=0 is y= 4/(sqrt(5))x+sqrt(5)

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tangent of f(x)=sqrt(5+8x),\at x=0

tangent of

f (x) = 5 + 8 x, at x = 0

y = \frac{4}{5} x + 5

Solution steps

Find the tangent point:

(0, 5)

Find the slope of

f (x) = 5 + 8 x : \frac{df ( x )}{d x} = \frac{4}{5 + 8 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{4}{5}

Find the line with slope m=

\frac{4}{5}

and passing through

(0, 5) : y = \frac{4}{5} x + 5

y = \frac{4}{5} x + 5

x \to \infty lim (x \cdot \frac{1}{x})

\frac{1}{120 x}

\int_{- 2}^{2} f (x) d x

\int x^{2} (3 + 4 x^{3})^{9} d x

x \to o lim (f (x, \frac{1}{x}))

What is the tangent of f(x)=sqrt(5+8x),\at x=0 ?
The tangent of f(x)=sqrt(5+8x),\at x=0 is y= 4/(sqrt(5))x+sqrt(5)